Solve $$ an ^{2}(2 heta)=1 $$, in the interval $$ -\frac{\pi}{2} \leqslant heta \leqslant \frac{\pi}{2} $$

Question

Solve $$ 	an ^{2}(2 	heta)=1 $$, in the interval $$ -\frac{\pi}{2} \leqslant 	heta \leqslant \frac{\pi}{2} $$

Horton Love · Accepted Answer

$$ 	heta = \frac{\pi}{8} + \frac{k\pi}{4} $$, where $$ k $$ is an integer.

Solve \( \tan ^{2}(2 \theta)=1 \), in the interval \( -\frac{\pi}{2} \leqslant \theta \leqslant \frac{\pi}{2} \)