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Question
\frac{1}{x+1}\times \frac{x^{2}}{5}
Simplify the expression
\frac{x^{2}}{5x+5}
Evaluate
\frac{1}{x+1}\times \frac{x^{2}}{5}
Multiply the terms
\frac{x^{2}}{\left(x+1\right)\times 5}
Multiply the terms
\frac{x^{2}}{5\left(x+1\right)}
Solution
More Steps
Evaluate
5\left(x+1\right)
Apply the distributive property
5x+5\times 1
Any expression multiplied by 1 remains the same
5x+5
\frac{x^{2}}{5x+5}
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Find the excluded values
x=-1
Evaluate
\frac{1}{x+1}\times \frac{x^{2}}{5}
To find the excluded values,set the denominators equal to 0
x+1=0
Move the constant to the right-hand side and change its sign
x=0-1
Solution
x=-1
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Find the roots
x=0
Evaluate
\frac{1}{x+1}\times \frac{x^{2}}{5}
To find the roots of the expression,set the expression equal to 0
\frac{1}{x+1}\times \frac{x^{2}}{5}=0
Find the domain
More Steps
Evaluate
x+1\neq 0
Move the constant to the right side
x\neq 0-1
Removing 0 doesn't change the value,so remove it from the expression
x\neq -1
\frac{1}{x+1}\times \frac{x^{2}}{5}=0,x\neq -1
Calculate
\frac{1}{x+1}\times \frac{x^{2}}{5}=0
Multiply the terms
More Steps
Multiply the terms
\frac{1}{x+1}\times \frac{x^{2}}{5}
Multiply the terms
\frac{x^{2}}{\left(x+1\right)\times 5}
Multiply the terms
\frac{x^{2}}{5\left(x+1\right)}
\frac{x^{2}}{5\left(x+1\right)}=0
Cross multiply
x^{2}=5\left(x+1\right)\times 0
Simplify the equation
x^{2}=0
The only way a power can be 0 is when the base equals 0
x=0
Check if the solution is in the defined range
x=0,x\neq -1
Solution
x=0
Show Solutions
