Little Park
12/01/2023 · Primary School
3. Resolver completamente el sistema, explicitando la solución general que origina todos los valores posibles \[ \begin{array}{l}3 x \equiv 2(\bmod 5) \\ 2 x \equiv 1(\bmod 3)\end{array} \]
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La solución general del sistema de congruencias es \(x \equiv 14 \pmod{15}\). Esto significa que todos los valores posibles de \(x\) son de la forma \(x = 15n + 14\) para algún \(n \in \mathbb{Z}\).
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