Munoz Griffiths
07/18/2023 · High School

\( (1-x)y^{\prime \prime }+xy^{\prime }-y=(1-x)^{2},y_{1}=e^{x} \)

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Para resolver la ecuación diferencial \((1-x)y^{\prime \prime } + xy^{\prime } - y = (1-x)^{2}\) con la condición inicial \(y(1) = e^{1}\), primero reescribe la ecuación en forma estándar y luego encuentra la solución homogénea y particular. La solución general es la suma de ambas, y se determinan las constantes aplicando la condición inicial.

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