\( 80-5 y \) when \( y=9 \)

When you substitute \( y = 9 \) into the expression \( 80 - 5y \), it becomes \( 80 - 5 \times 9 \). First, you multiply \( 5 \times 9 \) which gives you \( 45 \). Now, subtract \( 45 \) from \( 80 \): \[ 80 - 45 = 35. \] So, the result is \( 35 \). It's always a fun adventure when you plug in values and watch how the numbers dance around! Just don't forget to follow the order of operations to keep everything in line—it's the secret to getting to the right answer every time!