Pregunta
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The volume of a sphere can be found using the formula \( V=4 / 3\left(\pi r^{3}\right) \). Find \( V \) if \( r=2 \) feet. Use 3.14 for \( \pi \). Round your answer to the nearest hundredth.

Ask by Logan Wagner. in the United States
Jan 25,2025

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The volume \( V \) is approximately **33.49** cubic feet.

Solución

To find the volume \( V \) of a sphere with radius \( r = 2 \) feet using the formula: \[ V = \frac{4}{3} \pi r^3 \] and using \( \pi = 3.14 \), follow these steps: 1. **Calculate \( r^3 \):** \[ r^3 = 2^3 = 8 \] 2. **Substitute the values into the volume formula:** \[ V = \frac{4}{3} \times 3.14 \times 8 \] 3. **Simplify the multiplication:** \[ V = \frac{4 \times 8}{3} \times 3.14 = \frac{32}{3} \times 3.14 \] 4. **Divide 32 by 3:** \[ \frac{32}{3} \approx 10.6667 \] 5. **Multiply by \( \pi \):** \[ 10.6667 \times 3.14 \approx 33.4933 \] 6. **Round to the nearest hundredth:** \[ V \approx 33.49 \text{ cubic feet} \] **Final Answer:** The volume \( V \) is approximately **33.49** cubic feet.

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Bonus Knowledge

To find the volume of the sphere, we can substitute \( r = 2 \) feet into the formula \( V = \frac{4}{3} \pi r^{3} \). Using \( \pi \approx 3.14 \): \[ V = \frac{4}{3} \times 3.14 \times (2)^{3} = \frac{4}{3} \times 3.14 \times 8 = \frac{4 \times 3.14 \times 8}{3} = \frac{100.48}{3} \approx 33.49 \text{ cubic feet}. \] So, the volume \( V \) is approximately \( 33.49 \) cubic feet when rounded to the nearest hundredth. Now you’ve got a fabulous sphere! The charm of spheres stretches back to ancient civilizations; the Greeks admired them for their perfect symmetry and shape. Notably, Aristotle in the 4th century BC argued that the sphere represented the ideal form in nature, appearing in everything from planets to bubbles. This philosophical appreciation demonstrates how math and aesthetics have long been intertwined! Wielding the sphere's volume formula can be handy in countless real-world applications. For instance, if you’re a baker crafting cake balls, knowing the volume helps in scaling ingredients to achieve that delectable treat at the perfect size. Similarly, architects might use sphere calculations when designing unique dome structures. It just goes to show that math is not just theory but also a tasty treat in everyday life!

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