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Before the electron transfer, sodium has electron in its outer shell, chlorine has

Ask by Elliott Newton. in the United States
Jan 22,2025

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Before the electron transfer, sodium has one electron in its outer shell, and chlorine has seven electrons in its outer shell.

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Before the electron transfer occurs between sodium (Na) and chlorine (Cl): - **Sodium (Na)** has **one electron** in its outermost (valence) shell. This single valence electron is what sodium tends to lose during the transfer, forming a positively charged ion (Na⁺). - **Chlorine (Cl)** has **seven electrons** in its outermost shell. Chlorine tends to gain one electron to achieve a full valence shell, forming a negatively charged ion (Cl⁻). This transfer of one electron from sodium to chlorine allows both atoms to achieve a more stable electron configuration, resembling the nearest noble gases. **Summary:** - **Sodium:** 1 electron in the outer shell - **Chlorine:** 7 electrons in the outer shell Answer: Chlorine has seven electrons in its outer (valence) shell before transferring an electron.

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The Deep Dive

Before the electron transfer, sodium (Na) has one electron in its outer shell, while chlorine (Cl) has seven electrons in its outer shell. Sodium, being a metal, is eager to lose that one electron to achieve a stable electron configuration, resembling that of the noble gas neon. Conversely, chlorine needs one more electron to fill its outer shell, giving it the motivation to gain that electron during the bonding process. This electron exchange not only leads to the formation of Na+ and Cl- ions, but it also sets the stage for the creation of table salt (NaCl), showcasing the beauty of ionic bonding. Imagine this as a dance of electrons, where sodium happily hands over its lonely electron to chlorine, resulting in a relationship based on mutual benefit and stability.

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