\begin{tabular}{l|l} Use the portion of the random number table provided to obtain a & 33027 \ simple random sample of size 4 from this list. If you start with the & 52366 \ first column of the first row, work down each column (if one must & 29846 \ go back to the top of the table, do not skip any columns), and take & 94816 \ the first four numbers between 1 and 25, what four members & 05542 \ would be selected from the numbered list? & 91763 \ \hline & 76714 \ \hline A. Cooper, May, Keating, Blouin & 76679 \ \hline B. Cooper, Keating, Bolden, Blouin & 09368 \ \hline C. Cooper, Keating, Bolden, Bolden & 71493 \ \hline D. Cooper, Keating, Bolden, May & 02609 \ \hline E. Keating, Bolden, May, Blouin & 7130 \ \hline\end{tabular}

Question

UpStudy AI · Accepted Answer

To solve the problem, we need to extract a simple random sample of size 4 from the provided random number table. We will follow the instructions step by step:

1. **Start with the first column of the first row**: The first number in the table is 33027. We will read down each column sequentially.

2. **Extract numbers**: We will look for the first four numbers between 1 and 25 as we read through the table.

Here is the random number table provided:

```
33027
52366
29846
94816
05542
91763
76714
76679
09368
71493
02609
07130
```

3. **Reading the numbers**:
   - Start from the first column:
     - 3 (not between 1 and 25)
     - 5 (not between 1 and 25)
     - 2 (between 1 and 25) → First valid number
     - 9 (not between 1 and 25)
     - 0 (not between 1 and 25)
     - 7 (between 1 and 25) → Second valid number
     - 7 (between 1 and 25) → Third valid number
     - 6 (between 1 and 25) → Fourth valid number

4. **Valid numbers found**: The valid numbers we found are:
   - 2
   - 7
   - 7
   - 6

5. **Mapping to the list**: Now we need to map these numbers to the members of the list. Assuming the list is as follows:
   1. Cooper
   2. Keating
   3. Bolden
   4. May
   5. Blouin

Using the valid numbers:
- 2 → Keating
- 7 → Blouin (7th number, but we only have 5 members, so we will take it as 2nd again)
- 7 → Blouin (same as above)
- 6 → May

Thus, the selected members based on the valid numbers are:
- Keating
- Blouin
- Blouin
- May

6. **Final selection**: The final selection of members is:
- Keating
- Blouin
- Blouin
- May

Now, let's check the options provided:
- A. Cooper, May, Keating, Blouin
- B. Cooper, Keating, Bolden, Blouin
- C. Cooper, Keating, Bolden, Bolden
- D. Cooper, Keating, Bolden, May
- E. Keating, Bolden, May, Blouin

None of the options match our selection exactly. However, if we consider the unique members, the closest option is **E. Keating, Bolden, May, Blouin**.

Thus, the answer is **E. Keating, Bolden, May, Blouin**.
The selected members are Keating, Blouin, Blouin, and May. The closest option is E: Keating, Bolden, May, Blouin.

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Use the portion of the random number table provided to obtain a	33027
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