\begin{tabular}{l}\hline Question 9 N II Pause Q Zoom \\ \hline \\ Solve the system. \\ \( x+y=-1 \) \\ \( 3 x-y=5 \)\end{tabular}
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To solve the system of equations, we can use the substitution or elimination method. Let's use substitution for this example. From the first equation, \(x + y = -1\), we can express \(y\) as \(y = -1 - x\). Now, substitute this expression for \(y\) into the second equation: \(3x - (-1 - x) = 5\). This simplifies to: \(3x + 1 + x = 5\) \(4x + 1 = 5\) \(4x = 4\) \(x = 1\). Now plug \(x = 1\) back into the expression for \(y\): \(y = -1 - 1 = -2\). So, the solution to the system is \(x = 1\) and \(y = -2\). --- For a further twist, if you are curious, you can visualize this system geometrically! Each equation represents a line on a graph, and the point where they intersect is the solution. Thus, \( (1, -2) \) is where these two lines meet, confirming our algebraic solution! Also, watch out for common mistakes! A frequent error is misapplying signs when moving terms. Double-check your calculations, and remember that careful tracking of negative signs can save you from getting tangled up in the math!