Question 2 A car moves at a velocity with a solid wall. The car and comes to a standstill is 900 kg . 2.1 Calculate the impulse 2.2 Calculate the magnitu

To calculate the impulse and the magnitude of the impulse, we need to know the force applied to the car and the time over which the force is applied. Given: - Mass of the car: 900 kg - Velocity of the car: Not provided - Time: Not provided Let's assume the velocity of the car is \(v\) m/s and the time it takes for the car to come to a standstill is \(t\) seconds. 2.1 Calculate the impulse: The impulse of a force is given by the formula: \[ \text{Impulse} = \text{Force} \times \text{Time} \] Since the car comes to a standstill, the final velocity is 0 m/s. We can use the equation of motion to find the force applied: \[ F = m \times \frac{v_f - v_i}{t} \] where: - \(F\) is the force applied - \(m\) is the mass of the car - \(v_f\) is the final velocity (0 m/s) - \(v_i\) is the initial velocity (not provided) - \(t\) is the time 2.2 Calculate the magnitude of the impulse: The magnitude of the impulse is the same as the impulse itself, as it is a scalar quantity. Let's calculate the force applied first and then the impulse. Simplify the expression by following steps: - step0: Solution: \(\frac{900\left(0-v\right)}{t}\) - step1: Remove 0: \(\frac{900\left(-v\right)}{t}\) - step2: Multiply the numbers: \(\frac{-900v}{t}\) - step3: Calculate: \(-\frac{900v}{t}\) The force applied to the car is given by the equation: \[ F = -\frac{900v}{t} \] Now, let's calculate the impulse using the formula: \[ \text{Impulse} = \text{Force} \times \text{Time} \] Substitute the expression for the force into the formula for the impulse: \[ \text{Impulse} = -\frac{900v}{t} \times t \] Simplify the expression: \[ \text{Impulse} = -900v \] Therefore, the impulse is equal to the negative of the initial velocity of the car.