7) Mr. Jones is taking his family to see a play. There are 10 people going to the play, and they take 2 cars. Mr. Jones pays $$ \$ 5.50 $$ for parking for each car. He pays the same price for each ticket. Mr. Jones is charged a total of $$ \$ 142.00 $$ for tickets and parking. What is the price of each ticket to the play?

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UpStudy AI · Accepted Answer

Let's denote the price of each ticket as $$ x $$.

Given:
- Number of people going to the play: 10
- Number of cars: 2
- Parking cost per car: $5.50
- Total cost for tickets and parking: $142.00

We can set up the following equation based on the given information:
$$ 2 \times 5.50 + 10x = 142 $$

Now, we can solve this equation to find the price of each ticket.
Solve the equation by following steps:
- step0: Solve for $$x$$:
  $$2\times 5.5+10x=142$$
- step1: Multiply the numbers:
  $$11+10x=142$$
- step2: Move the constant to the right side:
  $$10x=142-11$$
- step3: Subtract the numbers:
  $$10x=131$$
- step4: Divide both sides:
  $$\frac{10x}{10}=\frac{131}{10}$$
- step5: Divide the numbers:
  $$x=\frac{131}{10}$$
The price of each ticket to the play is $13.10.
Each ticket costs $13.10.

Mr. Jones is taking his family to see a play. There are 10 people going to the play, and they take 2
cars. Mr. Jones pays for parking for each car. He pays the same price for each ticket. Mr. Jones
is charged a total of for tickets and parking. What is the price of each ticket to the play?

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Mr. Jones is taking his family to see a play. There are 10 people going to the play, and they take 2 cars. Mr. Jones pays for parking for each car. He pays the same price for each ticket. Mr. Jones is charged a total of for tickets and parking. What is the price of each ticket to the play?