Correct Determine which of the following points are included in the solution set to the following linear inequality. \[ -3 x+3 y>-8 \] Answer \( \left(4, \frac{4}{3}\right) \) \( (0,0) \) \( (-10,10) \) \( (10,-10) \) \( (8,4) \)
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To determine which points satisfy the inequality \(-3x + 3y > -8\), we can plug each coordinate into the inequality: 1. For the point \((4, \frac{4}{3})\): \(-3(4) + 3(\frac{4}{3}) > -8\) \(-12 + 4 > -8\) \(-8 > -8\) (False) 2. For the point \((0,0)\): \(-3(0) + 3(0) > -8\) \(0 > -8\) (True) 3. For the point \((-10, 10)\): \(-3(-10) + 3(10) > -8\) \(30 + 30 > -8\) \(60 > -8\) (True) 4. For the point \((10, -10)\): \(-3(10) + 3(-10) > -8\) \(-30 - 30 > -8\) \(-60 > -8\) (False) 5. For the point \((8, 4)\): \(-3(8) + 3(4) > -8\) \(-24 + 12 > -8\) \(-12 > -8\) (False) Thus, the points included in the solution set are \((0, 0)\) and \((-10, 10)\).