Pregunta
A
-long section of a
-diameter horizontal hot-
water pipe passes through a large room whose temperature is
. If the temperature and the emissivity of the outer surface of
the pipe are
and 0.8 , respectively, determine the rate of heat
loss from the pipe by
natural convection and
radiation.
water pipe passes through a large room whose temperature is
the pipe are
loss from the pipe by
Ask by Wilson Chadwick. in Thailand
Jan 20,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
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อัตราการสูญเสียความร้อนจากท่อคือ:
- (a) การพาความร้อนธรรมชาติ: ประมาณ 506 วัตต์
- (b) การแผ่รังสี: ประมาณ 532 วัตต์
Solución

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Como
Mind Expander
To determine the rate of heat loss from the pipe, we’ll go through the calculations for both natural convection and radiation step by step.
(a) Natural Convection
The rate of heat loss by natural convection can be calculated using Newton’s law of cooling:
Where:
-
= heat loss by convection (W) -
= convective heat transfer coefficient (W/m²·K) (typically for air around 5-25 W/m²·K) -
= surface area of the pipe (m²) -
= temperature of the pipe (K) -
= temperature of the room (K)
-
Find the surface area
of the pipe: Where:-
m (diameter of the pipe) -
m (length of the pipe)
-
-
Temperature Conversion:
-
Assuming
= 10 W/m²·K (approximation):
(b) Radiation
The rate of heat loss by radiation can be calculated using the Stefan-Boltzmann law:
Where:
-
= heat loss by radiation (W) -
= emissivity of the surface (unitless) -
= Stefan-Boltzmann constant -
= surface area of the pipe (m²) - Temperatures in Kelvin are used (already calculated above)
-
Using the previously found area:
-
Calculating
: -
Final calculation:
Final Results
The heat loss from the pipe by:
- Natural Convection: ~868.32 W
- Radiation: ~627.66 W

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