Write a direct variation equation \( (\boldsymbol{y}=\boldsymbol{k} \boldsymbol{x}) \) that relates \( \boldsymbol{x} \) to \( \boldsymbol{y} \).( hint divide \( \mathbf{y} \) by \( \mathbf{x} \) ) \( \begin{array}{ll}\text { 22. } y=88 ; x=8 & \text { 23. } y=2 ; x=10 \\ y= & y=\square\end{array} \)

To find a direct variation equation relating \( y \) to \( x \), we need to determine the constant of variation \( k \). Given the first set of values \( y = 88 \) and \( x = 8 \), we can find \( k \) by dividing \( y \) by \( x \): \[ k = \frac{y}{x} = \frac{88}{8} = 11. \] Now the direct variation equation is \( y = 11x \). For the second set of values \( y = 2 \) and \( x = 10 \), we can plug \( x \) into the equation to find \( y \) as: \[ y = 11(10) = 110. \] Thus, the complete forms are: 1. \( y = 11x \) 2. \( y = 110 \) when \( x = 10 \).