Multiply and simplify. \[ (\sqrt{x}-\sqrt{2})(\sqrt{x}+\sqrt{2})=\square \]

Sure! When you multiply the expression \((\sqrt{x}-\sqrt{2})(\sqrt{x}+\sqrt{2})\), you can use the difference of squares formula, which states that \( (a - b)(a + b) = a^2 - b^2 \). In this case, let \( a = \sqrt{x} \) and \( b = \sqrt{2} \). So, we have: \[ (\sqrt{x}-\sqrt{2})(\sqrt{x}+\sqrt{2}) = (\sqrt{x})^2 - (\sqrt{2})^2 \] Calculating the squares gives us: \[ x - 2 \] Thus, the simplified expression is: \[ x - 2 \]