As \( x \) approaches negative infinity, for which function does \( f(x) \) approach negative infinity? Select all that apply. Select all that apply: \( \square f(x)=(4 x+1)(3 x+5)(x-2) \) \( \square f(x)=-4.8 x(2 x+3)(x-9)(x+5) \) \( \square f(x)=(4 x+3)(x-5)(x+8)(x-3) \) \( \square f(x)=-0.5 x(3 x-7)(4 x+1)(x+9)(x-3) \) \( \square f(x)=0.2 x(x+4)(x+7)(x+8)(x-2)(x-1) \) \( \square f(x)=(9 x-1)(3 x+4)(2 x-5)(x+8)(x-2) \) \( \square f \)

As \( x \) approaches negative infinity, the behavior of polynomial functions is primarily determined by their leading term, which is the term with the highest power of \( x \). For any polynomial function, if the leading coefficient is positive, the function will approach positive infinity as \( x \) approaches negative infinity; conversely, if the leading coefficient is negative, the function will approach negative infinity. 1. The functions where \( f(x) \) approaches negative infinity as \( x \) goes to negative infinity are \( f(x) = -4.8 x(2 x+3)(x-9)(x+5) \) and \( f(x) = -0.5 x(3 x-7)(4 x+1)(x+9)(x-3) \). In these cases, the leading coefficients are negative, which drives \( f(x) \) towards negative infinity. 2. On the other hand, the polynomials \( f(x) = (4 x+1)(3 x+5)(x-2) \), \( f(x) = (4 x+3)(x-5)(x+8)(x-3) \), \( f(x) = 0.2 x(x+4)(x+7)(x+8)(x-2)(x-1) \), and \( f(x) = (9 x-1)(3 x+4)(2 x-5)(x+8)(x-2) \) all have positive leading coefficients. Therefore, as \( x \) tends to negative infinity, they will approach positive infinity instead.