$$ \left[\begin{array}{c}{(3^{2^{3}})\div (3^{1})^{5}+\sqrt {4^{3}}-39}\end{array}\right]+5^{0}= $$

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UpStudy AI · Accepted Answer

Calculate or simplify the expression $$ (3^{2^{3}})/(3^{1})^{5}+\sqrt{4^{3}}-39+5^{0} $$.
Calculate the value by following steps:
- step0: Calculate:
  $$\frac{3^{\left(2^{3}ight)}}{\left(3^{1}ight)^{5}}+\sqrt{4^{3}}-39+5^{0}$$
- step1: Evaluate the power:
  $$\frac{3^{\left(2^{3}ight)}}{\left(3^{1}ight)^{5}}+\sqrt{4^{3}}-39+1$$
- step2: Multiply the exponents:
  $$\frac{3^{\left(2^{3}ight)}}{3^{1	imes 5}}+\sqrt{4^{3}}-39+1$$
- step3: Multiply by $$a^{-n}:$$
  $$3^{\left(2^{3}ight)}	imes 3^{-5}+\sqrt{4^{3}}-39+1$$
- step4: Simplify:
  $$3^{\left(2^{3}ight)}	imes 3^{-5}+2^{3}-39+1$$
- step5: Multiply the numbers:
  $$3^{3}+2^{3}-39+1$$
- step6: Evaluate the power:
  $$27+2^{3}-39+1$$
- step7: Evaluate the power:
  $$27+8-39+1$$
- step8: Calculate:
  $$-3$$
La expresión $$ \left[\begin{array}{c}{(3^{2^{3}})\div (3^{1})^{5}+\sqrt {4^{3}}-39}\end{array}ight]+5^{0} $$ es igual a -3.
La expresión simplificada es -3.

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