Pregunta
A biologist uses the chi-square test to determine whether the observed distribution of 5
species matches an expected theoretical distribution. The chi-square test yields a
test
statistic of 11.143 .
What is the null hypothesis?
Select
What is the alternative hypothesis?
Select
What is the number of degrees of freedom? Ex: 5
What is the
-value? Ex: 1.23 .
Does the data differ from expected distribution at the
significance level?
Select
species matches an expected theoretical distribution. The chi-square test yields a
statistic of 11.143 .
What is the null hypothesis?
Select
What is the alternative hypothesis?
Select
What is the number of degrees of freedom? Ex: 5
What is the
Does the data differ from expected distribution at the
Select
Ask by Marsh Davison. in the United States
Dec 17,2024
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
Null Hypothesis (H0): The observed distribution of species matches the expected theoretical distribution.
Alternative Hypothesis (H1): The observed distribution of species does not match the expected theoretical distribution.
Number of degrees of freedom: 4.
p-value: [To be calculated].
Decision: [To be made based on the calculated p-value].
Alternative Hypothesis (H1): The observed distribution of species does not match the expected theoretical distribution.
Number of degrees of freedom: 4.
p-value: [To be calculated].
Decision: [To be made based on the calculated p-value].
Solución

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Bonus Knowledge
The null hypothesis claims that there is no significant difference between the observed distribution of species and the expected theoretical distribution, meaning any variation is due to random chance. The alternative hypothesis, on the other hand, proposes that there is a significant difference between the observed and expected distributions, indicating that something other than chance is influencing the observed frequencies.
To calculate the degrees of freedom for this test, you will take the number of categories (in this case, species) and subtract one. Therefore, with 5 species, the degrees of freedom will be
. For the p-value, you’d typically consult a chi-square distribution table or use software to find the probability corresponding to your test statistic of 11.143 with 4 degrees of freedom. If the p-value is less than 0.05, you would reject the null hypothesis, indicating that the data significantly differs from the expected distribution. Given the chi-square value, it is likely that you would reject the null hypothesis at the
significance level.

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