Payments with periodic rates. Denise has her heart set on being a millionaire. What payment does Denise need to make at the end of each month over the coming 40 years at \( 9 \% \) APR to reach her retirement goal of \( \$ 1.2 \) million? What monthly payment does Denise need to make to reach her retirement goal? \( \$ \square \) (Round to the nearest cenir)
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To calculate the monthly payment Denise needs to make in order to reach her retirement goal of $1.2 million in 40 years at a 9% annual interest rate, we can use the future value of an annuity formula. The formula is: \[ FV = P \times \frac{(1 + r)^n - 1}{r} \] Where: - \( FV \) is the future value ($1,200,000) - \( P \) is the monthly payment - \( r \) is the monthly interest rate (annual rate / 12) - \( n \) is the total number of payments (number of years × 12) Using \( r = 0.09 / 12 \approx 0.0075 \) and \( n = 40 \times 12 = 480 \), we rearrange the formula to solve for \( P \): \[ P = \frac{FV \times r}{(1 + r)^n - 1} \] Substituting the values: \[ P = \frac{1,200,000 \times 0.0075}{(1 + 0.0075)^{480} - 1} \] Calculating this yields: 1. Calculate \( (1 + 0.0075)^{480} \) which is approximately 10.932. 2. Then \( P \approx \frac{1,200,000 \times 0.0075}{10.932 - 1} \approx \frac{9,000}{9.932} \approx 905.93 \). Therefore, Denise needs to make a monthly payment of approximately \( \$905.93 \) to achieve her retirement goal of \( \$1.2 \) million in 40 years.