Groph the quadratic $$ y=x^{2}+3 x+8 $$. What is the $$ x $$-intercept(s)? (1 point)

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The quadratic equation $$ y = x^{2} + 3x + 8 $$ can be analyzed for $$ x $$-intercepts by setting $$ y = 0 $$:

$$
x^{2} + 3x + 8 = 0
$$

Using the quadratic formula:

$$
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
$$

where $$ a = 1 $$, $$ b = 3 $$, and $$ c = 8 $$:

$$
x = \frac{-3 \pm \sqrt{9 - 32}}{2} = \frac{-3 \pm \sqrt{-23}}{2}
$$

Since the discriminant ($$ \sqrt{-23} $$) is negative, there are no real $$ x $$-intercepts for this quadratic function.

**Answer:**  
There are no real x-intercepts because the quadratic has no real roots.
There are no real x-intercepts for the quadratic $$ y = x^{2} + 3x + 8 $$.

Groph the quadratic . What is the -intercept(s)? (1 point)

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