Use the given conditions to write an equation for the line in point-slope form and slope-intercept form Slope \( =-8 \), passing through \( (-6,-3) \) Type the point-slope form of the line \( \square \) (Simplify your answer Use integers or fractions for any numbers in the equation )

The point-slope form of the equation for a line is given by \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line. Here, the slope \( m = -8 \) and the point is \( (-6, -3) \). Plugging in these values, we get: \[ y + 3 = -8(x + 6) \] Now, let's convert this to slope-intercept form \( y = mx + b \) by simplifying: 1. Start with \( y + 3 = -8(x + 6) \). 2. Distribute \( -8 \): \( y + 3 = -8x - 48 \). 3. Subtract 3 from both sides: \( y = -8x - 51 \). So, the equations in the required forms are: Point-slope form: \( y + 3 = -8(x + 6) \) Slope-intercept form: \( y = -8x - 51 \)