Solve using algebra. Must show an opposite operation to both sides for full credi \( \begin{array}{ll}\text { 3. } \frac{x}{2}=8 & \text { 4. } x+14\end{array} \)

To solve \( \frac{x}{2} = 8 \), you want to eliminate the fraction by performing the opposite operation. Multiply both sides by 2: \[ x = 8 \times 2 \] \[ x = 16 \] Now, for the equation \( x + 14 = 0\), you'll want to isolate \( x \) by doing the opposite operation. Subtract 14 from both sides: \[ x + 14 - 14 = 0 - 14 \] \[ x = -14 \] There you have it: \( x = 16 \) for the first equation and \( x = -14 \) for the second one!