Factor \( x^{2}\left(6 x^{2}+8-26 x^{0}\right) \)

To factor the expression \( x^{2}(6 x^{2}+8-26 x^{0}) \), we first simplify it by recognizing that \( x^{0} = 1 \). This gives us: \[ x^{2}(6 x^{2} + 8 - 26) \] So, the expression simplifies to: \[ x^{2}(6 x^{2} - 18) \] Next, we can factor out the common terms inside the parentheses: \[ 6 x^{2} - 18 = 6(x^{2} - 3) \] Putting it all together, we have: \[ x^{2} \cdot 6(x^{2} - 3) = 6x^{2}(x^{2} - 3) \] Thus, the factored form of the expression is: \[ 6x^{2}(x^{2} - 3) \]