Graph the square root function \( y=-4 \sqrt{3 x-2} \). What is the starting value in the table for the function? (1 point) \( \begin{array}{l}x=2 \\ x=\frac{-8}{3} \\ x=\frac{2}{3} \\ x=\frac{3}{2}\end{array} \)

To graph the function \( y = -4 \sqrt{3x - 2} \), we first need to determine the starting value, which occurs when the expression under the square root is zero. Set \( 3x - 2 = 0 \) to find the x-value: \[ 3x = 2 \quad \Rightarrow \quad x = \frac{2}{3}. \] Therefore, the starting value in the table for the function is \( x = \frac{2}{3} \). When you graph the square root function, remember that the square root is only defined for non-negative values, so this influences where the graph starts. Since it starts from \( x = \frac{2}{3} \), the y-value will also start from zero at this point, and then decrease as x increases due to the negative coefficient in front of the square root. The function thus represents a downward-opening curve beginning at the point \( \left( \frac{2}{3}, 0 \right) \).