Find the equation of the given line. $$ (2,-3) \text { and }(1,-3) \text { on the line } $$

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To find the equation of the line that passes through the points $$(2, -3)$$ and $$(1, -3)$$, follow these steps:

### 1. **Determine the Slope (m)**

The slope of a line indicates its steepness and direction. It is calculated using the formula:

$$
m = \frac{y_2 - y_1}{x_2 - x_1}
$$

Let's plug in the given points $$(x_1, y_1) = (2, -3)$$ and $$(x_2, y_2) = (1, -3)$$:

$$
m = \frac{-3 - (-3)}{1 - 2} = \frac{0}{-1} = 0
$$

**Interpretation:** A slope of $$0$$ means the line is **horizontal**.

### 2. **Write the Equation of the Line**

For a horizontal line, the $$y$$-value is constant for all points on the line. Since both given points have a $$y$$-coordinate of $$-3$$, the equation of the line is:

$$
y = -3
$$

### 3. **Graphical Representation**

![Graph of the line y = -3](https://i.imgur.com/ZvKXFCz.png)

*The horizontal line $$y = -3$$ passes through both points $$(2, -3)$$ and $$(1, -3)$$.*

### 4. **Conclusion**

The equation of the line passing through the points $$(2, -3)$$ and $$(1, -3)$$ is:

$$
\boxed{y = -3}
$$
The equation of the line is $$ y = -3 $$.

Find the equation of the given line.

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