Pregunta
Question 8, 1.3.37 HW Score: \( \mathbf{2 6 . 0 9} \) 1.3 More on Functions and Craphs Part 1 of 2 Points: 0 of 1 Determine whether the function is even, odd, or neither. Then determine whether the function's graph is symmetric with respect to the \( y \)-axis, the origin, or neither. \[ f(x)=x^{5}-3 x \] Determine whether the function is even, odd, or neither. Choose the correct answer below. neither odd even
Ask by Ball Rodriguez. in the United States
Jan 25,2025
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The function \( f(x) = x^{5} - 3x \) is **odd** and its graph is symmetric with respect to the **origin**.
Solución
To determine whether the function \( f(x) = x^{5} - 3x \) is even, odd, or neither, we'll use the definitions of even and odd functions.
### Definitions:
- **Even Function:** A function \( f \) is even if for all \( x \) in its domain, \( f(-x) = f(x) \). Graphically, even functions are symmetric with respect to the \( y \)-axis.
- **Odd Function:** A function \( f \) is odd if for all \( x \) in its domain, \( f(-x) = -f(x) \). Graphically, odd functions are symmetric with respect to the origin.
- **Neither:** If a function does not satisfy either of the above conditions, it is neither even nor odd.
### Step-by-Step Analysis:
1. **Calculate \( f(-x) \):**
\[
f(-x) = (-x)^{5} - 3(-x) = -x^{5} + 3x
\]
2. **Compare \( f(-x) \) with \( f(x) \):**
\[
f(-x) = -x^{5} + 3x = -(x^{5} - 3x) = -f(x)
\]
Since \( f(-x) = -f(x) \), the function satisfies the condition for being an **odd function**.
### Conclusion:
- **Classification:** **Odd**
- **Graph Symmetry:** The graph of \( f(x) = x^{5} - 3x \) is symmetric with respect to the **origin**.
**Answer:** **odd**
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To determine if the function \( f(x) = x^{5} - 3x \) is even, odd, or neither, you can evaluate \( f(-x) \). First, calculate: \[ f(-x) = (-x)^{5} - 3(-x) = -x^{5} + 3x \] Now, compare \( f(-x) \) with \( f(x) \): - If \( f(-x) = f(x) \), the function is even. - If \( f(-x) = -f(x) \), the function is odd. - If neither is true, then it is neither. Since \( f(-x) = -f(x) \), this means the function is **odd**. This also tells us the graph is symmetric with respect to the origin. In summary, the function is odd.
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