Pregunta
- A winemaker has three kinds of wine. He has 400 litres of chenin blane,
440 litres chardonnay and 460 litres of sauvignon blanc. Calculate the
smallest possible number of barrels with equal volumes which can be fillec
with the different wines without mixing them so that no wine is left.
440 litres chardonnay and 460 litres of sauvignon blanc. Calculate the
smallest possible number of barrels with equal volumes which can be fillec
with the different wines without mixing them so that no wine is left.
Ask by Bates Norton. in South Africa
Jan 23,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
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To store all the wines without leftovers, each barrel must hold 20 litres. Therefore, the winemaker needs a total of 65 barrels.
Answer: 65 barrels are needed.
Solución

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Respondido por UpStudy AI y revisado por un tutor profesional
Como
Extra Insights
To solve this problem, we need to determine the greatest common divisor (GCD) of the volumes of the wines: 400 litres, 440 litres, and 460 litres. The GCD will give us the largest volume of a barrel that can be filled evenly without leaving any wine behind.
The prime factorization of each volume is as follows:
- 400 = 2^4 × 5^2
- 440 = 2^3 × 5 × 11
- 460 = 2 × 5 × 23
The GCD takes the lowest power of all prime factors common to the three numbers. For our case:
- The lowest power of 2 is 2^1.
- The lowest power of 5 is 5^1.
Thus, the GCD = 2^1 × 5^1 = 10 litres.
Now we can find the smallest possible number of barrels:
- For Chenin Blanc: 400 litres ÷ 10 litres = 40 barrels
- For Chardonnay: 440 litres ÷ 10 litres = 44 barrels
- For Sauvignon Blanc: 460 litres ÷ 10 litres = 46 barrels
In total, the smallest possible number of barrels needed is 40 + 44 + 46 = 130 barrels.

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