Activity 4: Change in momentum ( 40 minutes) 1 In each of the following cases: - Calculate the magnitude and direction of the ínitial momentum, final momentum and change in momentum of the object. - Draw a labelled vector diagram that shows the initial and final momentum of the object as well as its change in momentum. 1.1 A 1100 kg car accelerates along a straight road and its velocity increases from \( 10 \mathrm{~m} . \mathrm{s}^{-1} \) to \( 20 \mathrm{~m} . \mathrm{s}^{-1} \). 1.2 The brakes of a 1500 kg car are applied and its velocity decreases from \( 10 \mathrm{~m}_{\mathrm{s}} \mathrm{s}^{-1} \) to \( 2 \mathrm{~m} \cdot \mathrm{~s}^{-1} \). 1.3 A 440 g soccer ball approaches a goalkeeper at \( 8 \mathrm{~m} . \mathrm{s}^{-1} \) and he kicks it in the opposite direction at \( 10 \mathrm{~m} \cdot \mathrm{~s}^{-1} \)
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The Deep Dive
To determine the initial momentum, final momentum, and change in momentum for each case, we can use the formula for momentum, \( p = m \times v \). 1.1 For the car with a mass of 1100 kg: - Initial momentum: \( p_i = 1100 \, \text{kg} \times 10 \, \text{m/s} = 11,000 \, \text{kg m/s} \) in the direction of motion. - Final momentum: \( p_f = 1100 \, \text{kg} \times 20 \, \text{m/s} = 22,000 \, \text{kg m/s} \) in the same direction. - Change in momentum: \( \Delta p = p_f - p_i = 22,000 \, \text{kg m/s} - 11,000 \, \text{kg m/s} = 11,000 \, \text{kg m/s} \). 1.2 For the car with a mass of 1500 kg: - Initial momentum: \( p_i = 1500 \, \text{kg} \times 10 \, \text{m/s} = 15,000 \, \text{kg m/s} \) in the direction of motion. - Final momentum: \( p_f = 1500 \, \text{kg} \times 2 \, \text{m/s} = 3,000 \, \text{kg m/s} \) in the same direction. - Change in momentum: \( \Delta p = p_f - p_i = 3,000 \, \text{kg m/s} - 15,000 \, \text{kg m/s} = -12,000 \, \text{kg m/s} \) (the negative sign indicates a reduction in momentum). 1.3 For the 440 g soccer ball (which converts to 0.44 kg): - Initial momentum: \( p_i = 0.44 \, \text{kg} \times 8 \, \text{m/s} = 3.52 \, \text{kg m/s} \) towards the goalkeeper. - Final momentum: \( p_f = 0.44 \, \text{kg} \times -10 \, \text{m/s} = -4.4 \, \text{kg m/s} \) in the opposite direction. - Change in momentum: \( \Delta p = p_f - p_i = -4.4 \, \text{kg m/s} - 3.52 \, \text{kg m/s} = -7.92 \, \text{kg m/s} \). Now, to visualize this, draw vector diagrams showing both the initial and final momentum as arrows, with the change in momentum represented as an arrow that connects the tip of the initial momentum vector to the tip of the final momentum vector. This helps to depict not just the quantities, but the directions in which the objects are moving before and after.