\( \begin{array}{l}y=5 x-3 \\ x=y-5 \longrightarrow x=5 x-3-5 \\ \text { (1)) What is one way you can use substitution to solve this problem? } \\ \text { (1)) Substitute } 5 x-3 \text { for } y \\ \text { (1) Now, find the solution to the system of equations, } \\ (\square, \square)\end{array} \) ?

To solve the system of equations using substitution, we will follow these steps: 1. **Identify the equations:** We have the following two equations: \[ y = 5x - 3 \quad (1) \] \[ x = y - 5 \quad (2) \] 2. **Substitute \(y\) from equation (1) into equation (2):** We will substitute \(y\) in equation (2) with the expression from equation (1): \[ x = (5x - 3) - 5 \] 3. **Simplify the equation:** Now, we simplify the equation: \[ x = 5x - 3 - 5 \] \[ x = 5x - 8 \] 4. **Rearrange the equation:** To isolate \(x\), we can rearrange the equation: \[ x - 5x = -8 \] \[ -4x = -8 \] \[ x = 2 \] 5. **Substitute \(x\) back to find \(y\):** Now that we have \(x\), we can substitute it back into equation (1) to find \(y\): \[ y = 5(2) - 3 \] \[ y = 10 - 3 \] \[ y = 7 \] 6. **Final solution:** The solution to the system of equations is: \[ (x, y) = (2, 7) \] Thus, the final answer is \((2, 7)\).