Use fraction strips to find the sum. Write your answer in simplest form. \( \begin{array}{ll}5 \underline{2}+\underline{3}= & \text { 6. } \frac{1}{4}+\frac{1}{12}=\end{array} \)

To add the fractions \( \frac{1}{4} \) and \( \frac{1}{12} \), start by finding a common denominator. The least common multiple of 4 and 12 is 12. Rewrite \( \frac{1}{4} \) as \( \frac{3}{12} \) (since \( 1 \times 3 = 3 \) and \( 4 \times 3 = 12 \)). Then add: \[ \frac{3}{12} + \frac{1}{12} = \frac{4}{12}. \] Now simplify \( \frac{4}{12} \) by dividing the numerator and the denominator by their greatest common divisor, which is 4. So, \[ \frac{4 \div 4}{12 \div 4} = \frac{1}{3}. \] Thus, the sum \( \frac{1}{4} + \frac{1}{12} \) in simplest form is \( \frac{1}{3} \).