YOUR TEACHER Use an algebraic approach to solve the problem. Aura took three biology exams and has an average score of 88 . Her second exam score was 8 points better than her first, and her third exam score was 8 points better than her second exam. What were her three exam scores? (lowest score) (highest score)

To solve this problem algebraically, let's define the variables and set up an equation based on the given information. 1. **Define Variables:** - Let **\( x \)** be Aura's **first exam score**. - Her **second exam score** is **8 points higher** than the first, so it's **\( x + 8 \)**. - Her **third exam score** is **8 points higher** than the second, so it's **\( x + 16 \)**. 2. **Calculate the Total Score:** - The average score of the three exams is **88**, so the total score for all three exams is: \[ 88 \times 3 = 264 \] 3. **Set Up the Equation:** - Sum of the three exam scores: \[ x + (x + 8) + (x + 16) = 3x + 24 \] - According to the total score: \[ 3x + 24 = 264 \] 4. **Solve for \( x \):** \[ 3x + 24 = 264 \\ 3x = 264 - 24 \\ 3x = 240 \\ x = 80 \] 5. **Determine All Exam Scores:** - **First Exam:** \( x = 80 \) - **Second Exam:** \( x + 8 = 88 \) - **Third Exam:** \( x + 16 = 96 \) 6. **Identify the Lowest and Highest Scores:** - **Lowest Score:** 80 - **Highest Score:** 96 **Answer:** - **Lowest score:** 80 - **Highest score:** 96