\( c^{3}-1 \) when \( c=4 \)

First, let's evaluate \( c^3 - 1 \) when \( c = 4 \). Calculating \( 4^3 \) gives us \( 64 \), so now we can subtract 1: \[ 4^3 - 1 = 64 - 1 = 63 \] Thus, \( c^3 - 1 \) when \( c = 4 \) equals \( 63 \). Now, if you ever forget how to calculate cubes, just remember that \( n^3 \) means multiplying the number by itself three times—like a tiny math party! So if you can find the cube of any number, you'll be well on your way to tackling those polynomial equations like a pro! Also, be mindful of not confusing the operations: \( c^3 - 1 \) is often miscalculated by people who forget to cube first, leading to mistakes like just subtracting 1 from \( c \) instead of calculating \( c^3 \). Stay sharp!