The wind speed near the center of a tornado is represented by the equation \( S=93 \log d+65 \), where \( d \) is the distance, in miles, that the tornado travels and \( S \) is the wind speed, in miles per hour. If the tornado traveled 5.2 miles, what was its wind speed in miles per hour? Round your answer to one decimal place. You do not need to include units.

Substitute \( d=5.2 \) into the equation \( S=93 \log d+65 \). Evaluate the expression by following steps: - step0: Evaluate: \(S=93\log_{10}{\left(d\right)}+65\) - step1: Substitute: \(S=93\log_{10}{\left(5.2\right)}+65\) - step2: Convert the expressions: \(S=93\log_{10}{\left(\frac{26}{5}\right)}+65\) - step3: Simplify: \(S=93\log_{10}{\left(26\right)}-93\log_{10}{\left(5\right)}+65\) - step4: Check if the solution is in the defined range: \(S=93\log_{10}{\left(26\right)}-93\log_{10}{\left(5\right)}+65,d>0\) - step5: Find the intersection: \(\left\{ \begin{array}{l}S=93\log_{10}{\left(26\right)}-93\log_{10}{\left(5\right)}+65\\d>0\end{array}\right.\) The wind speed near the center of the tornado when it traveled 5.2 miles is approximately 131.588311 miles per hour. Rounding this to one decimal place, the wind speed is approximately 131.6 miles per hour.