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Suppose the odds against winning the lottery are \( 60,000,000 \) to 1 . What is the probability of the event of winning the lottery given these od \( P(E)=\frac{1}{60000000} \) (Type an integer or a simplified fraction.)

Ask by Thornton Paul. in the United States
Jan 22,2025

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The probability of winning the lottery is \( \frac{1}{60000000} \).

Solución

Given that the odds against winning the lottery are 60,000,000 to 1, we can calculate the probability of winning the lottery as follows: The probability of winning the lottery is the ratio of the number of favorable outcomes (1) to the total number of possible outcomes (60,000,000 + 1). Therefore, the probability of winning the lottery is \( P(E) = \frac{1}{60000000} \). To simplify this fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 1 in this case. Therefore, the probability of winning the lottery is \( P(E) = \frac{1}{60000000} \).

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Bonus Knowledge

Did you know that lotteries have been around for centuries? They’ve been used in ancient civilizations for everything from funding government projects to selecting heirs! The modern lottery as we know it started gaining popularity in the 16th century in Europe, and now, it’s become a multi-billion-dollar industry worldwide. Some even think of it as a fun game of chance, despite those astronomical odds! Now, if you’re thinking about playing the lottery, it’s crucial to keep a realistic mindset. Many people fall into the trap of believing they’ll be the lucky winner. A common mistake is playing too frequently or spending too much money on tickets. Remember, you’re much more likely to be struck by lightning than to win that jackpot! Just enjoy it for the thrill, and don't forget that it's a game of chance!

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