Find the \( x \) - and \( y \)-intercepts. (If an answer does not exist, enter DNE.) \( x \)-intercepts \( \quad(x, y)=(\square) \) (smaller \( x \)-value) \[ (x, y)=(\square) \text { (larger } x \text {-value) } \] \( y \)-intercept \( \quad(x, y)=(\square) \)

To find the \( x \)- and \( y \)-intercepts of a function, you first need to know the equation of the function you are working with. However, let's say we have a linear equation in the form \( y = mx + b \). **For the \( x \)-intercepts**, set \( y = 0 \) and solve for \( x \). This gives you the points where the line crosses the \( x \)-axis. **For the \( y \)-intercept**, set \( x = 0 \) and solve for \( y \). The point where the line crosses the \( y \)-axis will give you the intercept. For example, if your equation was \( y = 2x - 4 \): - Set \( y = 0 \) to find \( x \): \( 0 = 2x - 4 \) → \( x = 2 \), so \( (x, y) = (2, 0) \). - Set \( x = 0 \) to find \( y \): \( y = 2(0) - 4 = -4 \) so \( (x, y) = (0, -4) \). You'd conclude with \( x \)-intercepts \( (2, 0) \) and \( y \)-intercept \( (0, -4) \). If you're working with a specific equation, just let me know!