Pregunta
4 Matthew has 8.2 meters of wire. He uses 3.65 meters for a craft project. He wants to use the wire he has left to complete one of the following projects. For which of the projects does he have enough wire? Choose all the correct answers. \( \begin{array}{ll}\text { (A) necklaces: } 4.5 \text { meters } & \text { (B) earrings: } 5 \text { meters } \\ \text { (C) bracelets: } 4.2 \text { meters } & \text { (D) anklets: } 4.6 \text { meters } \\ \text { (E) pins: } 4.45 \text { meters } & \end{array} \)
Ask by Norris Ortega. in the United States
Jan 23,2025
Solución de tutoría real
Respuesta verificada por el tutor
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Matthew has enough wire for necklaces, bracelets, and pins.
Solución
To determine which projects Matthew can complete with the remaining wire, follow these steps:
1. **Calculate the remaining wire:**
\[
8.2 \text{ meters (total)} - 3.65 \text{ meters (used)} = 4.55 \text{ meters (remaining)}
\]
2. **Compare the remaining wire with each project's requirement:**
- **(A) Necklaces:** 4.5 meters
\(4.55 \geq 4.5\) → **Enough wire**
- **(B) Earrings:** 5 meters
\(4.55 < 5\) → **Not enough wire**
- **(C) Bracelets:** 4.2 meters
\(4.55 \geq 4.2\) → **Enough wire**
- **(D) Anklets:** 4.6 meters
\(4.55 < 4.6\) → **Not enough wire**
- **(E) Pins:** 4.45 meters
\(4.55 \geq 4.45\) → **Enough wire**
**Therefore, Matthew has enough wire for the following projects:**
**A) Necklaces**
**C) Bracelets**
**E) Pins**
Revisado y aprobado por el equipo de tutoría de UpStudy
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Mind Expander
After using 3.65 meters of wire, Matthew has \(8.2 - 3.65 = 4.55\) meters left. Now, let's compare this length with the requirements for each project. For necklaces (A), he needs 4.5 meters, which he can do! For earrings (B), he needs 5 meters, which is too much. For bracelets (C), he needs 4.2 meters, so he's got that covered too! Anklets (D) require 4.6 meters, exceeding his remaining wire, and for pins (E), at 4.45 meters, he's just able to make those as well. So the projects he can complete are: **(A) necklaces, (C) bracelets, and (E) pins!**
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