Hanif works out the range of \( 1 \frac{9}{10}, 3 \frac{7}{8}, 1 \frac{3}{4}, 2 \frac{3}{11} \) and 3 He writes \( 3 \frac{1}{3}-1 \frac{9}{10}=1 \frac{13}{20} \) He is wrong. Work out the correct range.

To find the correct range, we need to subtract the smallest number from the largest number in the given set of numbers. Given numbers: \(1 \frac{9}{10}, 3 \frac{7}{8}, 1 \frac{3}{4}, 2 \frac{3}{11}, 3\) First, let's convert the mixed numbers to improper fractions: \(1 \frac{9}{10} = \frac{19}{10}\), \(3 \frac{7}{8} = \frac{31}{8}\), \(1 \frac{3}{4} = \frac{7}{4}\), \(2 \frac{3}{11} = \frac{25}{11}\), \(3 = \frac{30}{10}\). Now, we can find the correct range by subtracting the smallest number from the largest number: Range = Largest number - Smallest number Range = \(\frac{31}{8} - \frac{19}{10}\) Let's calculate the range. Calculate the value by following steps: - step0: Calculate: \(\frac{31}{8}-\frac{19}{10}\) - step1: Reduce fractions to a common denominator: \(\frac{31\times 5}{8\times 5}-\frac{19\times 4}{10\times 4}\) - step2: Multiply the numbers: \(\frac{31\times 5}{40}-\frac{19\times 4}{10\times 4}\) - step3: Multiply the numbers: \(\frac{31\times 5}{40}-\frac{19\times 4}{40}\) - step4: Transform the expression: \(\frac{31\times 5-19\times 4}{40}\) - step5: Multiply the numbers: \(\frac{155-19\times 4}{40}\) - step6: Multiply the numbers: \(\frac{155-76}{40}\) - step7: Subtract the numbers: \(\frac{79}{40}\) The correct range is \(1 \frac{39}{40}\) or 1.975.