12. A Video Game service has a membership plan in which a person pays a membership fee of $$ \$ 20 $$ plus $$ \$ 2.50 $$ for each game rented. Non-members pay $$ \$ 5.00 $$ for each game rented. How many games would a person need to rent to make the membership plan a better deal?

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To determine when the membership plan becomes a better deal compared to paying as a non-member, we can set up the following equations based on the costs: 1. **Membership Plan Cost:** $$ \text{Total Cost} = \$20 + \$2.50 \times \text{Number of Games (x)} $$ 2. **Non-Member Cost:** $$ \text{Total Cost} = \$5.00 \times \text{Number of Games (x)} $$ We want to find the smallest integer value of $$ x $$ for which the membership cost is **less than** the non-member cost: $$ 20 + 2.50x < 5x $$ **Solving the inequality:** $$ 20 < 5x - 2.50x $$ $$ 20 < 2.50x $$ $$ x > \frac{20}{2.50} $$ $$ x > 8 $$ Since $$ x $$ must be a whole number (you can't rent a fraction of a game), the smallest integer greater than 8 is **9**. **Conclusion:** A person needs to rent **9 or more games** to make the membership plan a better deal than paying per game as a non-member. Answer: **9** A person needs to rent **9 or more games** to make the membership plan a better deal.

A Video Game service has a membership plan in which a person pays a membership fee of plus
for each game rented. Non-members pay for each game rented. How many games would a person need to
rent to make the membership plan a better deal?

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A Video Game service has a membership plan in which a person pays a membership fee of plus for each game rented. Non-members pay for each game rented. How many games would a person need to rent to make the membership plan a better deal?