Look at the replacement set below. $$ \{0,4,5,13\} $$ Which number from the replacement set is $$ a^{\text {don }} $$ solution of the inequality $$ 8 \geq 5+x $$ ? $$ \begin{array}{llll}\text { A. } 0 & \text { B. } 4 & \text { C. } 5 & \text { D. } 13\end{array} $$

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To solve the inequality $$ 8 \geq 5 + x $$, we first isolate $$ x $$.

1. Subtract 5 from both sides:
   $$
   8 - 5 \geq x
   $$
   This simplifies to:
   $$
   3 \geq x
   $$
   or equivalently,
   $$
   x \leq 3
   $$

Now, we need to determine which number from the replacement set $$ \{0, 4, 5, 13\} $$ satisfies the condition $$ x \leq 3 $$.

- Checking each number:
  - $$ 0 \leq 3 $$ (True)
  - $$ 4 \leq 3 $$ (False)
  - $$ 5 \leq 3 $$ (False)
  - $$ 13 \leq 3 $$ (False)

The only number from the replacement set that satisfies the inequality $$ x \leq 3 $$ is $$ 0 $$.

Thus, the answer is:
$$
\boxed{0}
$$
The number from the replacement set that is a solution to the inequality $$ 8 \geq 5 + x $$ is $$ 0 $$.

Look at the replacement set below.

Which number from the replacement set is
solution of the inequality ?

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Look at the replacement set below. Which number from the replacement set is solution of the inequality ?