\begin{tabular}{l|l}\( \square \) & Question 3 \\ \( 2-3 x<5 x-22 \) \\ \( \bigcirc x>-12 \) \\ \( \bigcirc x<3 \) \\ \( O x>3 \) \\ \( O x<12 \)\end{tabular}
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Let's have a little fun with inequalities! The inequality \( 2 - 3x < 5x - 22 \) can be solved like a mystery novel. Move your x-terms to one side and constant terms to the other. Rearranging gives \( 2 + 22 < 5x + 3x \), eventually leading to \( 24 < 8x \), which simplifies to \( x > 3 \). Now, for the second inequality, \( x > -12 \) introduces the idea of boundaries. While this condition is very lenient and allows for a wide range of x-values, combining it with the first inequality, we focus on \( x > 3 \). So, the only valid solution is \( x > 3 \), leaving us with the thrill of finding that sweet spot for x!