Solve using substitution. \[ \begin{array}{l}10 x-8 y=18 \\ x=5\end{array} \]

Solve the system of equations \( 10x-8y=18;x=5 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}10x-8y=18\\x=5\end{array}\right.\) - step1: Substitute the value of \(x:\) \(10\times 5-8y=18\) - step2: Simplify: \(50-8y=18\) - step3: Move the constant to the right side: \(-8y=18-50\) - step4: Subtract the numbers: \(-8y=-32\) - step5: Change the signs: \(8y=32\) - step6: Divide both sides: \(\frac{8y}{8}=\frac{32}{8}\) - step7: Divide the numbers: \(y=4\) - step8: Calculate: \(\left\{ \begin{array}{l}x=5\\y=4\end{array}\right.\) - step9: Check the solution: \(\left\{ \begin{array}{l}x=5\\y=4\end{array}\right.\) - step10: Rewrite: \(\left(x,y\right) = \left(5,4\right)\) The solution to the system of equations using substitution is \( (x,y) = (5,4) \).