(c) \( \left(\frac{16 x^{9} y^{3}}{x y^{11}}\right)^{-1 / 2} \)
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To simplify the expression \( \left(\frac{16 x^{9} y^{3}}{x y^{11}}\right)^{-1 / 2} \), start by simplifying the fraction inside the parentheses. This gives: \[ \frac{16 x^{9} y^{3}}{x y^{11}} = 16 x^{9-1} y^{3-11} = 16 x^{8} y^{-8}. \] Now rewriting this fraction in a more manageable form yields: \[ 16 x^{8} y^{-8} = \frac{16 x^{8}}{y^{8}}. \] Now, apply the exponent of \(-\frac{1}{2}\): \[ \left(\frac{16 x^{8}}{y^{8}}\right)^{-1/2} = \frac{1}{\left(\frac{16 x^{8}}{y^{8}}\right)^{1/2}} = \frac{1}{\frac{4 x^{4}}{y^{4}}} = \frac{y^{4}}{4 x^{4}}. \] So, the final simplified form of the expression is: \[ \frac{y^{4}}{4 x^{4}}. \]