2.) Which equation is true if \( y=1 \) ? \( \begin{array}{ll}\text { A. } 3 y=2 y+8 & \text { C. } 1-2 y=3 y-9 \\ \text { B. } 4 y+5 y=3 y+6 & \text { D. } y=3 y-1\end{array} \)
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Let's substitute \( y = 1 \) into each equation and see which one holds true. A. \( 3(1) = 2(1) + 8 \) becomes \( 3 = 2 + 8 \), which simplifies to \( 3 = 10 \) – not true! B. \( 4(1) + 5(1) = 3(1) + 6 \) becomes \( 4 + 5 = 3 + 6 \), which simplifies to \( 9 = 9 \) – true! C. \( 1 - 2(1) = 3(1) - 9 \) becomes \( 1 - 2 = 3 - 9 \), which simplifies to \( -1 = -6 \) – not true! D. \( 1 = 3(1) - 1 \) becomes \( 1 = 3 - 1 \), which simplifies to \( 1 = 2 \) – not true! So the correct equation is B: \( 4y + 5y = 3y + 6 \). If you want to check this quickly, substitute \( y = 1 \) into the others first to rule them out! It's a great technique to use with any equations you come across!