\begin{tabular}{l} Consider the following set of real numbers: \\ \( \left\{\pi,-\sqrt{3},-0.5,0, \frac{1}{7}, \sqrt{5}, \sqrt{9}, 3 . \overline{3}\right\} \) \\ Which of the following contains ALL of the irrational numbers in the set? \\ \( \begin{array}{l}\pi,-\sqrt{3}, \sqrt{5}, \sqrt{9} \\ \\ \pi,-\sqrt{3}, \sqrt{5} \\ \\ -\sqrt{3}, \sqrt{5}, \sqrt{9}, 3 . \overline{3}\end{array} \) \\ \( \begin{array}{l}\pi\end{array} \) \\ \( \begin{array}{l}\pi\end{array} \) \\ \hline\end{tabular}
Solución de tutoría real
Responder
Solución
Revisado y aprobado por el equipo de tutoría de UpStudy
Bonus Knowledge
Among the given numbers, irrational numbers are those that cannot be expressed as a fraction of two integers. In our set, \(\pi\), \(-\sqrt{3}\), and \(\sqrt{5}\) are irrational, while \(\sqrt{9}\) equals 3, which is rational, and the rest of the numbers (like \(-0.5\), \(0\), \(\frac{1}{7}\), and \(3.\overline{3}\)) are also rational. So, the selection containing all the irrational numbers is \(\pi, -\sqrt{3}, \sqrt{5}\). Interestingly, numbers like \(\pi\) and \(-\sqrt{3}\) have not only captured mathematicians' attention for centuries but also artists and writers, inspiring countless works that explore the relationship between the infinite and the aesthetic. If you're venturing into the world of irrational numbers, it's vital to recognize that they possess unique properties, like being non-repeating and non-terminating when expressed in decimal form. A common mistake is assuming that all radicals produce irrational numbers, which isn't true; \(\sqrt{9}\) reminds us that the square root of perfect squares yields rational results!