Pregunta
So for, Maya has learned \( 58 \% \) of her spelling words. Her sister Becky has learned \( \frac{7}{12} \) of her spelling words. Who has learned a greater percentage of her spelling words, Maya or Becky? Maya Becky
Ask by Conner Best. in the United States
Jan 23,2025
Solución de tutoría real
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Becky has learned a greater percentage of her spelling words than Maya.
Solución
To determine who has learned a greater percentage of their spelling words, let's compare Maya's and Becky's progress:
1. **Maya's Progress:**
- Maya has learned **58%** of her spelling words.
2. **Becky's Progress:**
- Becky has learned \( \frac{7}{12} \) of her spelling words.
- To convert this fraction to a percentage:
\[
\frac{7}{12} \times 100\% = \frac{700}{12}\% \approx 58.33\%
\]
**Comparison:**
- **Maya:** 58%
- **Becky:** Approximately 58.33%
**Conclusion:**
Becky has learned a slightly greater percentage of her spelling words compared to Maya.
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The Deep Dive
To compare the percentages, let's convert Becky's fraction into a percentage. \( \frac{7}{12} \) can be calculated as \( 7 \div 12 \approx 0.5833 \), which is approximately \( 58.33\% \). Since Maya has learned \( 58\% \) of her spelling words, and Becky has learned approximately \( 58.33\% \), Becky has learned a greater percentage of her spelling words. So, Becky has learned more spelling words than Maya!
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