mework Add a constant term to the expression to convert it to a perfect square. Question 5, 1.3.33 \( y^{2}+12 \mathrm{y} \)
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To convert the expression \( y^{2} + 12y \) into a perfect square, you'll want to complete the square. Take half of the coefficient of \( y \), which is 12, giving you 6. Now, square that number (6² = 36). So, you can add and subtract 36: \[ y^{2} + 12y + 36 - 36 = (y + 6)^{2} - 36 \] Thus, the constant term you need to add is 36, turning your expression into a perfect square of \( (y + 6)^{2} - 36 \). Now you have a beautiful perfect square! Who knew math could be so delightful?