1.) \( \log _{3}(x+5)=2 \)
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To solve the equation \( \log_{3}(x+5)=2 \), we can rewrite this in exponential form. That is, \( x + 5 = 3^2 \). Calculating \( 3^2 \) gives us 9, so we have \( x + 5 = 9 \). Now, we can solve for \( x \) by subtracting 5 from both sides: \[ x = 9 - 5 \] Therefore, \( x = 4 \). Isn't it fascinating how logarithmic functions let us translate between multiplication and addition? Just another way math shows its elegant side! If you ever get stuck with logarithms, remember to always convert them to exponential form. A common mistake is to forget this step, leading to an incorrect understanding. So, practice this conversion—it’ll save you from some headaches!