\( \sum _ { p = 5 } ^ { m } ( 2 - 3 p ) = - 7085 \)
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To solve the equation \( \sum _ { p = 5 } ^ { m } ( 2 - 3 p ) = - 7085 \), let's start by calculating the sum explicitly. The expression inside the summation can be rearranged: \( 2 - 3p \) is a linear function. When we sum from \( p = 5 \) to \( m \), we can calculate the sum of the first few terms and then use the formula for the sum of an arithmetic series. Now, the sum can be split: \( \sum (2 - 3p) = \sum 2 - 3 \sum p \). The first part simplifies to \( 2(m - 4) \) since we're summing the constant 2 for \( m - 4 \) terms. The second part calculates to \( 3 \cdot \frac{m(m + 1)}{2} - \frac{4 \cdot 5}{2} \). By equating this to -7085 and solving for \( m \), we find the largest integer that will satisfy the initial summation equation. Remember to check for integer values of \( m \) that could possibly yield a correct calculation as this sum is defined for integer inputs only! Use consistent checks and simple arithmetic to avoid common mistakes in these equations.