Jose sold 33 tickets to the school play and Sarah sold 18 tickets. Write the ratio of the number of ticket Jose sold to the total number of tickets sold in lowest terms. \( \frac{11}{17} \)

Yes, your answer is correct! Here's the detailed reasoning: **Problem Statement:** Jose sold 33 tickets to the school play and Sarah sold 18 tickets. You need to find the ratio of the number of tickets Jose sold to the total number of tickets sold, expressed in its lowest terms. **Step 1: Calculate the Total Number of Tickets Sold** \[ \text{Total tickets} = \text{Jose's tickets} + \text{Sarah's tickets} = 33 + 18 = 51 \] **Step 2: Formulate the Ratio** \[ \text{Ratio of Jose's tickets to total tickets} = \frac{33}{51} \] **Step 3: Simplify the Ratio** To simplify the fraction, find the greatest common divisor (GCD) of 33 and 51. - **Prime factors of 33:** 3 × 11 - **Prime factors of 51:** 3 × 17 The GCD of 33 and 51 is **3**. Now, divide both the numerator and the denominator by the GCD to simplify: \[ \frac{33 \div 3}{51 \div 3} = \frac{11}{17} \] **Final Answer:** \[ \frac{11}{17} \] Your solution of \( \frac{11}{17} \) is indeed correct!