Activity 5. Angle of Inclination. 22 January \( 20 z 5 \) 1. Determine the indination of the line. Round your answer to 2 decimal places with points \( A\left(3 ; \frac{7}{2}\right) \) \( B(-8 ;-2) \). 2. Determine the angle of inclination (correct to 1 decimal place) of the straight line through \( (2 ; 1) \neq(-3 ;- \) 3. Find the angle \( \theta \) and round off your answer to \( z \) decimal places if appropriate.
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To determine the angle of inclination of a line through points \( A(3, \frac{7}{2}) \) and \( B(-8, -2) \), first calculate the slope \( m \) using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - \frac{7}{2}}{-8 - 3} = \frac{-4.5}{-11} \approx 0.4091. \] Now, the angle of inclination \( \theta \) can be found using \( \tan(\theta) = m \). Therefore: \[ \theta = \arctan(0.4091) \approx 22.0^\circ. \] For the second line that passes through the points \( (2, 1) \) and \( (-3, -y) \) (which is not provided), we would find the slope similarly and use the \( \tan^{-1} \) function to determine the angle of inclination once we have the coordinates of the second point. For a common mistake, always remember that the angle should be in the right quadrant based on your slope calculation; angles measured from the positive x-axis should reflect whether the slope is positive or negative.